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NEW QUESTION: 1
Where should a consultant look for LMS Integration resources? ( 2 corrects )
A. HCM Cloud Partner Services
B. SAP Integration Services
C. SAP Service Marketplace
D. HCM Help Portal
Answer: A,C
NEW QUESTION: 2
Given the code in a file Traveler.java:
And the commands:
Javac Traveler.java
Java Traveler Java Duke
What is the result?
A. Happy Journey! Duke
B. Happy Journey! Java
C. The program fails to execute due to a runtime error
D. An exception is thrown at runtime
Answer: C
NEW QUESTION: 3
あなたはMicrosoft SQL Server2012のサーバー上でホストされるアプリケーションのデータベース開発者です。データベースはの定義を持つ2つのテーブルが含まれています:
グローバルな顧客はいくつかの国から注文を出します。あなたは各顧客が最も発注してから国を表示する必要があります。
どのTransact-SQLのクエリは使用すべきか。
A. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM (SELECT c.CustomerID, c.CustomerName, o.ShippingCountry,
RANK() OVER (PARTITION BY CustomerID ORDER BY COUNT(o.OrderAmount) ASC) AS Rnk FROM Customer c INNER JOIN Orders o ON c.CustomerID = o.CustomerID GROUP BY c.CustomerID, c.CustomerName, o.ShippingCountry) cs WHERE Rnk = 1
B. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer c INNER JOIN (SELECT CustomerID, ShippingCountry, RANK() OVER (PARTITION BY CustomerID ORDER BY COUNT(OrderAmount) DESC) AS Rnk FROM Orders GROUP BY CustomerID, ShippingCountry) AS o ON c.CustomerID = o.CustomerID WHERE o.Rnk = 1
C. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer c INNER JOIN (SELECT CustomerID, ShippingCountry, COUNT(OrderAmount) DESC) AS OrderAmount FROM Orders GROUP BY CustomerID, ShippingCountry) AS o ON c.CustomerID = o.CustomerID ORDER BY OrderAmount DESC
D. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer c INNER JOIN (SELECT CustomerID, ShippingCountry, RANK() OVER (PARTITION BY CustomerID ORDER BY OrderAmount DESC) AS Rnk FROM Orders GROUP BY CustomerID, ShippingCountry) AS o ON c.CustomerID = o.CustomerID WHERE o.Rnk = 1
Answer: B