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NEW QUESTION: 1
Which of the following commands would display the lines containing capital letters form the file "turkey.txt"?
A. cat turkey.txt|wc -w [A-Z]
B. cat turkey.txt|wc -|
C. grep -v [A-Z] < turkey.txt
D. for [A-Z]in turkey.txt | count
E. grep -n [A-Z] turkey.txt
Answer: E

NEW QUESTION: 2
Your customer requires a Mid-Year review and Annual Review for the current business process to work in Oracle Performance Management Cloud. They have a Self-Evaluation step in both the performance templates but they would like to notify the employee's manager about the completion of the Self-Evaluation step only in the Annual Review Document to reduce the mail traffic.
Which statement is correct about implementing this requirement?
A. The Notify Manager check box will be not selected in the Overall Summary section in the Mid-Year review template and this will be selected for the Annual review template.
B. This notification cannot be controlled at the performance template level and once turned on will fire for the step for all the Performance templates.
C. The Notify Manager check box will be deselected in the Mid-Year review template and will be selected for the Annual review template.
D. The Activity Name for Manager Role will be left bank for the Mid-Year review process flow.
Answer: D

NEW QUESTION: 3
Your network contains a System Center 2012 R2 Configuration Manager Service Pack 1 (SP1) environment.
You need to create a report that lists all of the client computers that do not have an Application named App1 installed.
Which query should you use to create the report?
A. SELECT SYS.Netbios_Name0, ARP.DisplayName0FROM v_R_System AS SYS INNER JOINV_GS_ADD_REMOVE_PROGRAMS AS ARP ON SYS.ResourceID - ARP.ResourceID WHERE ARP.DisplayName0NOT LIKE 'App1'
B. SELECT SYS.Netbios_Name0 from v_R_System SYSWHERE SYS.ResourceID NOT IN(SELECT SYS.ResourceIDFROM v_R_SystemAS SYS INNER JOINv_GS_ADD_REMOVE_PROGRAMS AS ARP ON SYS.ResourceID = ARP.ResourceID WHERE ARP.DisplayName0 = 'App1')
C. SELECT SYS.Netbios_Name0 from v_R_System SYSWHERE SYS.ResourceID IN(SELECT SYS.ResourceIDFROM v_R_System ASSYS INNER JOINv_GS_ADD_REMOVE_PROGRAMS AS ARP ON SYS.ResourceID - ARP.ResourceID. WHERE ARP.DisplayName0 = 'App1')
D. SELECTSYS.Netbios_Name0, ARP.DisplayName0FROM v_R_System AS SYS INNER JOINv_GS_ADD_REMOVE_PROGRAMS AS ARP ON SYS.ResourceID = ARP. ResourceID WHERE ARP.DisplayName0 NOT IN ('App1')
Answer: B
Explanation:
Explanation/Reference:
Explanation:
SELECT computer name FROM table v_R_System (SQL Syntax)
WHERE resource ResourceID is NOT IN
Add Remove Programs WHERE DisplayName0 = 'App1'
SQL INNER JOIN Keyword
The INNER JOINkeyword returns rows when there is atleast one match in both tables.