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NEW QUESTION: 1
소스 및 개체 버전이 같은지 확인하기 위해 프로그램 샘플을 선택할 때 IS 감사자가 수행하는 다음 테스트는 무엇입니까?
A. 프로그램 컴파일러 컨트롤의 실질적인 테스트
B. 프로그램 라이브러리 제어의 적합성 테스트
C. 프로그램 라이브러리 제어에 대한 실질적인 테스트
D. 프로그램 컴파일러 컨트롤의 적합성 테스트
Answer: B
Explanation:
설명:
컴플라이언스 테스트는 컨트롤이 설계된대로 작동하고 관리 정책 및 절차를 준수하는 방식으로 적용되고 있는지 확인합니다. 예를 들어, IS 감사자가 프로그램 라이브러리 제어가 올바르게 작동하는지 여부를 우려하는 경우, IS 감사자는 소스 및 오브젝트 버전이 동일한 지 판별하기 위해 프로그램 샘플을 선택할 수 있습니다. 다시 말해, 모든 준수 테스트의 광범위한 목표는 감사가 예비 평가에서 감사자가 인식 한대로 감사자가 의지 할 특정 통제가 운영되고 있다는 합리적인 확신을 감사에게 제공하는 것입니다.
NEW QUESTION: 2
An engineer must design a Cisco VSS-based configuration within a customer campus network. The two VSS switches are provisioned for the campus distribution layer and each one has a single supervisor and multiple 10 gigabit line cards. Which option is the primary reason to avoid plugging both VSL links into the supervisor ports?
A. The design lacks optimal hardware diversity
B. Limited bandwidth is available for VSS convergence
C. The implementation creates a loop
D. QoS is required on the VSL links
Answer: A
Explanation:
Explanation: The best-practice recommendation for VSL link resiliency is to bundle two
10-Gbps ports from different sources. Doing this might require having one port from the supervisor and other from a Cisco 6708 line card.
When configuring the VSL, note the following guidelines and restrictions:
For line redundancy, we recommend configuring at least two ports per switch for the VSL.
For module redundancy, the two ports can be on different switching modules in each chassis.
NEW QUESTION: 3
展示を参照してください。
ルーティングプロトコル間で再配布が有効になり、PC2、PC3、およびPC4がPC1に到達できない。問題を解決する2つの解決策は何ですか? (2つ選択してください。)
A. R2のRIPに再配布するときにRIPルートをフィルターしてRIPに戻す
B. R2でOSPFに再配布するときに、RIPおよびOSPFルートをフィルターしてEIGRPからOSPFに戻します
C. R2のEIGRPに再配布するときに、RIPルートを除くすべてのルートをフィルタリングします。
D. R3でOSPFに再配布するときに、EIGRPルートを除くすべてのルートをフィルタリングします。
E. R2のRIPに再配布するときに、OSPFルートをRIP FROM EIGRPにフィルターします。
Answer: A,E
Explanation:
Explanation
Even PC2 cannot reach PC1 so there is something wrong with RIP redistribution in R2. Because RIP has higher Administrative Distance (AD) value than OSPF and EIGRP so it will be looped when doing mutual redistribution.