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NEW QUESTION: 1
Sie haben einen Server mit dem Namen Server1, auf dem Windows Server 2012 R2 ausgeführt wird. Auf Server1 ist die Hyper-V-Serverrolle installiert.
Sie müssen NIC-Teaming auf Server1 implementieren.
Welche zwei Netzwerkverbindungen sollten Sie in das NIC-Team aufnehmen? (Wählen Sie zum Beantworten die beiden entsprechenden Netzwerkverbindungen im Antwortbereich aus.)

Answer:
Explanation:

Erläuterung

Für das NIC-Teaming ist ein einzelner Ethernet-Netzwerkadapter erforderlich, der zum Trennen von Datenverkehr verwendet werden kann, der VLANs verwendet. Alle Modi, die Fehlerschutz durch Failover bieten, erfordern mindestens zwei Ethernet-Netzwerkadapter. NIC1 ist bereits aktiviert, daher sollten Sie NIC2 und NIC3 einschließen.
Referenz: http://technet.microsoft.com/en-us/library/hh831648.aspx

NEW QUESTION: 2
Blockchain services consists of three major components.
What are they? (Select three.)
A. Distributed Ledger
B. Membership Services
C. Reputation Manager
D. Consensus Manager
E. Peer to Peer Protocol
Answer: A,D,E
Explanation:
Explanation/Reference:
Explanation:
1. P2P Protocol is implemented over HTTP/2 standards and uses Google RPC.. P2P components define messages used by peer nodes, from point to point to multicast. 2. Distributed Ledger manages the world state and the transaction log in the blockchain. 3. Consensus Manager defines the interface between the consensus algorithm and the other Hyperledger components.

NEW QUESTION: 3
Refer to the exhibit.

You are bringing a new MPLS router online and have configured only what in nhown to bring LDP up. Annume that the
peer han been configured in a nimilar manner. You verify the LDP peer ntate and nee that there are no neighborn. What
will the output of nhow mpln ldp dincovery nhow?
A. Interfacen:
Ethernet0/0 (ldp): xmit/recv
LDP Id: 25.25.25.2:0; IP addr: 192.168.12.2
B. Interfacen:
Ethernet0/0 (ldp): xmit
C. Interfacen:
Ethernet0/0 (ldp): xmit/recv
LDP Id: 25.25.25.2:0; no route
D. Interfacen:
Ethernet0/0 (ldp): xmit/recv
LDP Id: 192.168.12.2:0; no route
Answer: C