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NEW QUESTION: 1
In a social network, what does it mean for a node to have a high degree but low betweenness?
A. The node acts as the hub of the graph.
B. The node is adjacent to a few nodes, each of each has high Page Ranks.
C. The node can be easily bypassed by communications taking other shorter paths.
D. The node has the only edge connecting its community to the rest of the graph.
Answer: A
NEW QUESTION: 2
Instructions
Branch2ネットワーク10.1 0.20.0 / 24がGREトンネルを介してServer farm1ネットワーク10.1 0.10.0 / 24と通信できないのはなぜですか？
A. The GRE tunnel destination is not configured on the R2 router.
B. The static route points to the tunnel0 interface that is misconfigured on the R2 router.
C. The GRE tunnel destination is not configured on the Branch2 router.
D. The static route points to the tunnel0 interface that is misconfigured on the Branch2 router.
Answer: D
Explanation:
The Branch2 network is communicating to the Server farm, which is connected to R2, via GRE Tunnel so we should check the GRE tunnel first to see if it is in "up/up" state with the "show ip interface brief" command on the two routers.
On Branch2:
On R2:
We see interfaces Tunnel0 at two ends are "up/up" which are good so we should check for the routing part on two routers with the "show running-config" command and pay attention to the static routing of each router. On Branch2 we see:
The destination IP address for this static route is not correct. It should be 192.168.24.1 (Tunnel0's IP address of R2), not 192.168.24.10 -> Answer C is correct.
Note: You can use the "show ip route" command to check the routing configuration on each router but if the destination is not reachable (for example: we configure "ip route 10.10.10.0 255.255.255.0 192.168.24.10" on Branch2, but if 192.168.24.10 is unknown then Branch2 router will not display this routing entry in its routing table.
NEW QUESTION: 3
あなたは小さなIT企業であるROUTE.comのネットワークエンジニアです。最近、2つの組織を統合しましたが、トポロジの展示に示すように、ネットワークを統合する必要があります。 1つのネットワークはIGPとしてOSPFを使用しており、もう1つのネットワークはIGPとしてEIGRPを使用しています。 OSPFネットワークとEIGRPネットワーク間の相互接続を提供するために、R4が既存のOSPFネットワークに追加されました。冗長性を提供する2つのリンクが追加されました。
ネットワーク要件には、R1のループバック101から172.16.1.100のOPSFドメインテストアドレスにpingおよびtelnetできる必要があると記載されています。すべてのトラフィックは、最大の帯域幅を提供する最短パスを使用する必要があります。リンク障害が発生した場合、OSPFネットワークからEIGRPネットワークへの冗長パスが利用可能でなければなりません。どちらのネットワークでも静的またはデフォルトのルーティングは許可されていません。
以前のネットワークエンジニアが合併の実装を開始し、すべてのIPアドレス指定と基本的なIGPルーティングを正常に割り当てて検証しました。実装を完了し、ネットワーク要件が満たされていることを確認する必要があります。現在、どのルーターでも設定コマンドを削除または変更することはできません。新しいコマンドを追加したり、デフォルト値を変更したりできます。
A. 詳細な回答については、この部分を確認してください。
最初に、再配布のためのs0 / 0/0インターフェイス（R4に接続されたR2のインターフェイス）の5つのパラメーター（帯域幅、遅延、信頼性、負荷、MTU）を見つける必要があります。
R2＃show interface s0 / 0/0
これらの5つのパラメーターを書き留めます。メトリック単位は数十マイクロ秒であるため、Delayを10で割る必要があることに注意してください。たとえば、Bandwidth = 1544 Kbit、Delay = 20000 us、Reliability = 255、Load = 1、MTU = 1500バイトを取得したら、次のように再配布します。
R2#config terminal
R2(config)# router ospf 1
R2(config-router)# redistribute eigrp 100 metric-type 1 subnets
R2(config-router)#exit
R2(config-router)#router eigrp 100
R2(config-router)#redistribute ospf 1 metric 1544 2000 255 1 1500
Note: In fact, these parameters are just used for reference and we can use other parameters with no problem.
If the delay is 20000us then we need to divide it by 10, that is 20000 / 10 = 2000) For R3 we use the show interface fa0/0 to get 5 parameters too R3#show interface fa0/0 For example we get Bandwidth=10000 Kbit, Delay=1000 us, Reliability=255, Load=1, MTU=1500 bytes R3#config terminal R3(config)#router ospf 1 R3(config-router)#redistribute eigrp 100 metric-type 1 subnets R3(config)#exit R3(config-router)#router eigrp 100 R3(config-router)#redistribute ospf 1 metric 10000 100 255 1 1500 Finally you should try to "show ip route" to see the 172.16.100.1 network (the network behind R4) in the routing table of R1 and make a ping from R1 to this network.
Note: If the link between R2 and R3 is FastEthernet link, we must put the command below under EIGRP process to make traffic from R1 to go through R3 (R1 -> R2 -> R3 -> R4), which is better than R1 -> R2 -> R4.
R2(config-router)# distance eigrp 90 105
This command sets the Administrative Distance of all EIGRP internal routes to 90 and all EIGRP external routes to 105, which is smaller than the Administrative Distance of OSPF (110) -> the link between R2 & R3 will be preferred to the serial link between R2 & R4.
Note: The actual OPSF and EIGRP process numbers may change in the actual exam so be sure to use the actual correct values, but the overall solution is the same.
B. Check this part for details answer.
First we need to find out 5 parameters (Bandwidth, Delay, Reliability, Load, MTU) of the s0/0/0 interface (the interface of R2 connected to R4) for redistribution:
R2#show interface s0/0/0
Write down these 5 parameters, notice that we have to divide the Delay by 10 because the metric unit is in tens of microsecond. For example, we get Bandwidth=1544 Kbit, Delay=20000 us, Reliability=255, Load=1, MTU=1500 bytes then we would redistribute as follows:
R2#config terminal
R2(config)# router ospf 1
R2(config-router)#redistribute ospf 1 metric 1544 2000 255 1 1500
Note: In fact, these parameters are just used for reference and we can use other parameters with no problem.
If the delay is 20000us then we need to divide it by 10, that is 20000 / 10 = 2000) For R3 we use the show interface fa0/0 to get 5 parameters too R3#show interface fa0/0 For example we get Bandwidth=10000 Kbit, Delay=1000 us, Reliability=255, Load=1, MTU=1500 bytes R3#config terminal R3(config)#router ospf 1 Note: If the link between R2 and R3 is FastEthernet link, we must put the command below under EIGRP process to make traffic from R1 to go through R3 (R1 -> R2 -> R3 -> R4), which is better than R1 -> R2 -> R4.
R2(config-router)# distance eigrp 90 105
This command sets the Administrative Distance of all EIGRP internal routes to 90 and all EIGRP external routes to 105, which is smaller than the Administrative Distance of OSPF (110) -> the link between R2 & R3 will be preferred to the serial link between R2 & R4.
Note: The actual OPSF and EIGRP process numbers may change in the actual exam so be sure to use the actual correct values, but the overall solution is the same.
Answer: A