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NEW QUESTION: 1
You have compromised a server and successfully gained a root access. You want to pivot and pass traffic undetected over the network and evade any possible Intrusion Detection System.
What is the best approach?
A. Install and use Telnet to encrypt all outgoing traffic from this server.
B. Use HTTP so that all traffic can be routed via a browser, thus evading the internal Intrusion Detection Systems.
C. Use Alternate Data Streams to hide the outgoing packets from this server.
D. Install Cryptcat and encrypt outgoing packets from this server.
Answer: D
Explanation:
Explanation/Reference:
Cryptcat enables us to communicate between two systems and encrypts the communication between them with twofish.
References: http://null-byte.wonderhowto.com/how-to/hack-like-pro-create-nearly-undetectable-backdoor- with-cryptcat-0149264/
NEW QUESTION: 2
A. Option D
B. Option C
C. Option E
D. Option A
E. Option B
Answer: C,D,E
Explanation:
C: Wrong: When the machine is starting up the Ballooning driver hasn't loaded yet.D: Wrong: When VMware tools is not installed Ballooning isn't possible
NEW QUESTION: 3
Note: This question is part of a series of questions that use the same or similar answer choices. An answer choice may be correct for more than one question in the series. Each question is independent of the other questions in this series. Information and details provided in a question apply to that question.
You have a database for a banking system. The database has two tables named tblDepositAcct and tblLoanAcct that store deposit and loan accounts, respectively. Both tables contain the following columns:
You need to determine the total number of deposit and loan accounts.
Which Transact-SQL statement should you run?
A. SELECT COUNT (DISTINCT COALESCE(D.CustNo, L.CustNo))
FROM tblDepositAcct D
FULL JOIN tblLoanAcct L ON D.CustNo =L.CustNo
WHERE D.CustNo IS NULL OR L.CustNo IS NULL
B. SELECT COUNT(*)
FROM (SELECT CustNo
FROM tblDepositAcct
UNION
SELECT CustNo
FROM tblLoanAcct) R
C. SELECT COUNT(*)
FROM tblDepositAcct D
FULL JOIN tblLoanAcct L ON D.CustNo = L.CustNo
D. SELECT COUNT(*)
FROM (SELECT CustNo
FROM tblDepositAcct
EXCEPT
SELECT CustNo
FROM tblLoanAcct) R
E. SELECT COUNT(*)
FROM (SELECT AcctNo
FROM tblDepositAcct
INTERSECT
SELECT AcctNo
FROM tblLoanAcct) R
F. SELECT COUNT (DISTINCT D.CustNo)
FROM tblDepositAcct D, tblLoanAcct L
WHERE D.CustNo = L.CustNo
G. SELECT COUNT(DISTINCT L.CustNo)
FROM tblDepositAcct D
RIGHT JOIN tblLoanAcct L ON D.CustNo =L.CustNo
WHERE D.CustNo IS NULL
H. SELECT COUNT(*)
FROM (SELECT CustNo
FROMtblDepositAcct
UNION ALL
SELECT CustNo
FROM tblLoanAcct) R
Answer: H
Explanation:
Explanation/Reference:
Explanation:
Would list the customers with duplicates, which would equal the number of accounts.
Incorrect Answers:
A: INTERSECT returns distinct rows that are output by both the left and right input queries operator.
B: Would list the customers without duplicates.
D: Number of customers.
F: EXCEPT returns distinct rows from the left input query that aren't output by the right input query.
References:
https://msdn.microsoft.com/en-us/library/ms180026.aspx