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NEW QUESTION: 1
Which of the following distribution assumptions will produce the lowest probability of exceeding an extreme value, assuming identical means and variances?
A. t-distribution
B. a normal distribution
C. a distribution with kurtosis = 5
D. a normal mixture distribution
Answer: B
Explanation:
Explanation
An 'extreme value' will be a value that will lie in the tails. We need to determine the distribution that will have the least weight in the tails so that the probability of exceeding this tail value is minimum across the given choices.
The t-distribution, a distribution with kurtosis > 3 and a normal mixture distribution are all distributions with tails fatter than that for a normal distribution. A normal distribution will have the 'thinnest' tails among the choices and therefore the lowest probability of exceeding a given tail event value.
A note about the t-distribution: Leptokurtic distributions (those that have kurtosis>3, ie kurtosis greater than that for a normal distribution) generally appear to have higher peaks on their PDF graphs. The t-distribution is flatter, and actually appears lower than a normal distribution, which may make one think that it has a lower kurtosis and therefore should have thinner tails than a normal distribution. But that is not so, and the "visual" inspection test fails for inferring the kurtosis from just looking a the shape of the distribution. The kurtosis of a t-distribution is given by the formula {3 + 6/(d - 4)}, where d is the degrees of freedom and d > 4. Therefore the kurtosis of a t-distribution is always greater than 3 as "6/(d-4)" will always be a positive number being added to 3. Therefore there is no conflict between a t-distribution having fatter tails than a normal distribution as it has a higher kurtosis, even though it appears 'lower' on a graph when superimposed with a normal distribution.
NEW QUESTION: 2
How can you assign the Review New Hire Data step to a hiring Manager?
2 Correct ANS:
A. Add an HRIS element in the user data file.
B. Create a custom HRIS element as an MDF object
C. Set rule SAP_ONB2_HMReviewCheck to true
D. Set up RBP
Answer: C,D
NEW QUESTION: 3
View the Exhibit and examine the structure in the EMPLOYEES tables.
Evaluate the following SQL statement:
SELECT employee_id, department_id
FROM employees
WHERE department_id= 50 ORDER BY department_id
UNION
SELECT employee_id, department_id
FROM employees
WHERE department_id=90
UNION
SELECT employee_id, department_id
FROM employees
WHERE department_id=10;
What would be the outcome of the above SQL statement?
A. The statement would not execute because the ORDER BY clause should appear only at the end of the SQL statement, that is, in the last SELECT statement.
B. The statement would execute successfully but it will ignore the ORDER BY clause and display the rows in random order.
C. The statement would execute successfully and display all the rows in the ascending order of DEPARTMENT_ID.
D. The statement would not execute because the positional notation instead of the column name should be used with the ORDER BY clause.
Answer: A
NEW QUESTION: 4
Refer to the output of the corporate router routing table shown in the graphic.
The corporate router receives an IP packet with a source IP address of 192.168.214.20 and a destination address of 192.168.22.3.
What will the router do with this packet?
A. It will discard the packet and send an ICMP Destination Unreachable message out interface FastEthernet 0/0.
B. It will encapsulate the packet as Frame Relay and forward it out interface Serial 0/0.117.
C. It will change the IP packet to an ARP frame and forward it out FastEthernet 0/0.
D. It will forward the packet out interface Serial 0/1 and send an ICMP Echo Reply message out interface serial 0/0.102.
Answer: A
Explanation:
Since the destination network is not in the routing table, and no default gateway has been configured, the router will discard the packet and send an ICMP Destination Unreachable message out interface FastEthernet 0/0. It knows to send it out Fa 0/0 because the routing table for the source IP address of 192.168.214.20 shows it was learned from the Fa 0/0 interface.