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NEW QUESTION: 1
A system administrator who was using an account with elevated privileges deleted a large amount of log files generated by a virtual hypervisor in order to free up disk space. These log files are needed by the security team to analyze the health of the virtual machines. Which of the following compensating controls would help prevent this from reoccurring? (Select two.)
A. Personnel training
B. Separation of duties
C. Job rotation
D. Succession planning
E. Mandatory vacation
Answer: A,B
Explanation:
Explanation/Reference:
Explanation:
NEW QUESTION: 2
In the Fibre Channel protocol, what are functions of the FC-1 layer?
A. Interface mapping and flow control
B. Routing and flow control
C. Transmission of raw bits and encoding
D. Encoding and decoding
Answer: D
Explanation:
FC-1 Layer: It defines how data is encoded prior to transmission and decoded upon receipt. At the transmitter node, an 8-bit character is encoded into a 10-bit transmission character. This character is then transmitted to the receiver node. At the receiver node, the 10-bit character is passed to the FC-1 layer, which decodes the 10-bit character into the original 8-bit character. FC links with speed 10 Gbps and above use 64-bit to 66-bit encoding algorithm. This layer also defines the transmission words such as FC frame delimiters, which identify the start and end of a frame and primitive signals that indicate events at a transmitting port. In addition to these, the FC-1 layer performs link initialization and error recovery. EMC E10001 Student Resource Guide. Module 5: Fibre Channel Storage Area Network (FC SAN)
NEW QUESTION: 3
Which two options are ways in which an OSPFv3 router handles hello packets with a clear address-family bit? (Choose two.)
A. IPv6 unicast packets are discarded.
B. IPv4 unicast packets are discarded.
C. IPv4 unicast packets are forwarded.
D. IPv6 unicast packets are forwarded.
Answer: B,D
Explanation:
Explanation/Reference:
Explanation:
A typical distance vector protocol saves the following information when computing the best path to a destination: the distance (total metric or distance, such as hop count) and the vector (the next hop). For instance, all the routers in the network in Figure 1 are running Routing Information Protocol (RIP). Router Two chooses the path to Network A by examining the hop count through each available path.
Since the path through Router Three is three hops, and the path through Router One is two hops, Router Two chooses the path through One and discards the information it learned through Three. If the path between Router One and Network A goes down, Router Two loses all connectivity with this destination until it times out the route of its routing table (three update periods, or 90 seconds), and Router Three re- advertises the route (which occurs every 30 seconds in RIP). Not including any hold-down time, it will take between 90 and 120 seconds for Router Two to switch the path from Router One to Router Three.
EIGRP, instead of counting on full periodic updates to re-converge, builds a topology table from each of its neighbor's advertisements (rather than discarding the data), and converges by either looking for a likely loop-free route in the topology table, or, if it knows of no other route, by querying its neighbors. Router Two saves the information it received from both Routers One and Three. It chooses the path through One as its best path (the successor) and the path through Three as a loop-free path (a feasible successor). When the path through Router One becomes unavailable, Router Two examines its topology table and, finding a feasible successor, begins using the path through Three immediately.
Reference: http://www.cisco.com/c/en/us/support/docs/ip/enhanced-interior-gateway-routing- protocol- eigrp/16406-eigrp-toc.html