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NEW QUESTION: 1
A penetration tester successfully exploits a system, receiving a reverse shell.
Which of the following is a Meterpreter command that is used to harvest locally stored credentials?
A. background
B. session
C. getuid
D. psexec
E. hashdump
Answer: E
NEW QUESTION: 2
Refer to the exhibit. Assume that all deployed switches are with Supervisor 1 and M-Series line cards. Which statement about the implementation of Cisco FabricPath in the core at sites S1 and S2 is true?
A. OTV and FabricPath cannot coexist on the same switch due to differences in frame formats.
B. An upgrade to Supervisor 2E is required for FabricPath support.
C. Site S3 should also have FabricPath implemented to ensure optimal traffic flows.
D. Installation of additional linecards such as F2 or F2e linecards is required.
Answer: D
NEW QUESTION: 3
ユーザーストーリーによると、製品は非常に高速である必要があります。
デモ中、製品所有者は製品の速度に不満を持っています。
これが発生した最も可能性の高い理由は、ユーザーストーリーが次の理由でした。
A. テストできません。
B. 正しく見積もられていません。
C. 値の説明ではありません。
D. 大きすぎる。
Answer: A
NEW QUESTION: 4
You administer a Microsoft SQL Server 2012 database named ContosoDb. Tables are defined as shown in the exhibit. (Click the Exhibit button.)
You need to display rows from the Orders table for the Customers row having the
CustomerId value set to 1 in the following XML format:
< row OrderId="1" OrderDate="2000-01-01T00:00:00" Amount="3400.00"
Name="Customer
A" Country="Australia" />
< row OrderId="2" OrderDate="2001-01-01T00:00:00" Amount="4300.00"
Name="Customer
A" Country="Australia" />
Which Transact-SQL query should you use?
A. SELECT OrderId, OrderDate, Amount, Name, Country
FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId
WHERE Customers.CustomerId = 1
FOR XML AUTO
B. SELECT Name, Country, OrderId, OrderDate, Amount
FROM Orders INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId
WHERE Customers.CustomerId = 1
FOR XML AUTO, ELEMENTS
C. SELECT Name, Country, OrderId, OrderDate, Amount
FROM Orders INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId
WHERE Customers.CustomerId = 1
FOR XML AUTO
D. SELECT OrderId, OrderDate, Amount, Name, Country
FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId
WHERE Customers.CustomerId = 1
FOR XML RAW, ELEMENTS
E. SELECT Name AS 'Customers/Name', Country AS 'Customers/Country', OrderId,
OrderDate, Amount
FROM Orders INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId
WHERE Customers.CustomerId = 1
FOR XML PATH ('Customers')
F. SELECT OrderId, OrderDate, Amount, Name, Country
FROM Orders INNER JOIN Customers ON Orders.CustomerId - Customers.CustomerId
WHERE Customers.CustomerId = 1
FOR XML AUTO, ELEMENTS
G. SELECT OrderId, OrderDate, Amount, Name, Country
FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId
WHERE Customers.CustomerId = 1
FOR XML RAW
H. SELECT Name AS '@Name', Country AS '@Country', OrderId, OrderDate, Amount
FROM Orders INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId
WHERE Customers.CustomerId = 1
FOR XML PATH ('Customers')
Answer: G
Explanation:
Reference: http://msdn.microsoft.com/en-us/library/bb510464.aspx