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NEW QUESTION: 1
Where should a consultant look for LMS Integration resources? ( 2 corrects )
A. SAP Service Marketplace
B. HCM Help Portal
C. SAP Integration Services
D. HCM Cloud Partner Services
Answer: A,D
NEW QUESTION: 2
Given the code in a file Traveler.java:
And the commands:
Javac Traveler.java
Java Traveler Java Duke
What is the result?
A. Happy Journey! Java
B. An exception is thrown at runtime
C. Happy Journey! Duke
D. The program fails to execute due to a runtime error
Answer: D
NEW QUESTION: 3
あなたはMicrosoft SQL Server2012のサーバー上でホストされるアプリケーションのデータベース開発者です。データベースはの定義を持つ2つのテーブルが含まれています:
グローバルな顧客はいくつかの国から注文を出します。あなたは各顧客が最も発注してから国を表示する必要があります。
どのTransact-SQLのクエリは使用すべきか。
A. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer c INNER JOIN (SELECT CustomerID, ShippingCountry, COUNT(OrderAmount) DESC) AS OrderAmount FROM Orders GROUP BY CustomerID, ShippingCountry) AS o ON c.CustomerID = o.CustomerID ORDER BY OrderAmount DESC
B. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer c INNER JOIN (SELECT CustomerID, ShippingCountry, RANK() OVER (PARTITION BY CustomerID ORDER BY OrderAmount DESC) AS Rnk FROM Orders GROUP BY CustomerID, ShippingCountry) AS o ON c.CustomerID = o.CustomerID WHERE o.Rnk = 1
C. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM (SELECT c.CustomerID, c.CustomerName, o.ShippingCountry,
RANK() OVER (PARTITION BY CustomerID ORDER BY COUNT(o.OrderAmount) ASC) AS Rnk FROM Customer c INNER JOIN Orders o ON c.CustomerID = o.CustomerID GROUP BY c.CustomerID, c.CustomerName, o.ShippingCountry) cs WHERE Rnk = 1
D. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer c INNER JOIN (SELECT CustomerID, ShippingCountry, RANK() OVER (PARTITION BY CustomerID ORDER BY COUNT(OrderAmount) DESC) AS Rnk FROM Orders GROUP BY CustomerID, ShippingCountry) AS o ON c.CustomerID = o.CustomerID WHERE o.Rnk = 1
Answer: D